-6x^2-96x-90=0

Solution for -6x^2-96x-90=0 equation:

-6x^2-96x-90=0

a = -6; b = -96; c = -90;
Δ = b2-4ac
Δ = -962-4·(-6)·(-90)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-84}{2*-6}=\frac{12}{-12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+84}{2*-6}=\frac{180}{-12}
=-15
$